Math, asked by NAGASAKI3251, 10 months ago

2x^2+x+4=0 solve by the method of completing the square

Answers

Answered by rkmurthy1644
2

Step-by-step explanation:

hence this will be the correct answer

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Answered by AkashMathematics
1

2x^2+x+4=0 This can be written as,

2x2 + x = -4

Dividing both sides of the equation by 2, we get

⇒ x² + 1/2x = 2

⇒ x² + 2 × x × 1/4 = -2

By adding (1/4)² to both sides of the equation, we get

⇒ (x)² + 2 × x × 1/4 + (1/4)² = (1/4)² – 2

⇒ (x + 1/4)² = 1/16 – 2

⇒ (x + 1/4)² = -31/16

As we know, the square of numbers cannot be negative.

Therefore, there is no real root for the given equation, 2x² + x + 4 = 0.

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