2x^2+x+4=0 solve by the method of completing the square
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2x^2+x+4=0 This can be written as,
⇒ 2x2 + x = -4
Dividing both sides of the equation by 2, we get
⇒ x² + 1/2x = 2
⇒ x² + 2 × x × 1/4 = -2
By adding (1/4)² to both sides of the equation, we get
⇒ (x)² + 2 × x × 1/4 + (1/4)² = (1/4)² – 2
⇒ (x + 1/4)² = 1/16 – 2
⇒ (x + 1/4)² = -31/16
As we know, the square of numbers cannot be negative.
Therefore, there is no real root for the given equation, 2x² + x + 4 = 0.
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