Question

2x^2+(x-4)^2=5x(x-4)+24 find roots​

Answer 1

Answer :

x = 3 ± 5

Solution :

• Given : 2x² + (x - 4)² = 5x(x - 4) + 24

• To find : x = ?

We have ,

=> 2x² + (x - 4)² = 5x(x - 4) + 24

=> 2x² + x² - 8x + 16 = 5x² - 20x + 24

=> 3x² - 8x + 16 = 5x² - 20x + 24

=> 5x² - 3x² - 20x + 8x + 24 - 16 = 0

=> 2x² - 12x + 8 = 0

=> 2(x² - 6x + 4) = 0

=> x² - 6x + 4 = 0

=> (x² - 6x + 3²) - 3² + 4 = 0

=> (x - 3)² - 9 + 4 = 0

=> (x - 3)² - 5 = 0

=> (x - 3)² = 5

=> x - 3 = ±5

=> x = 3 ± 5

Hence , x = 3 ± 5 .

Answer 2

Answer:

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