Question

2x^2-x+5=0.
Find the value of x​

Answer 1

Answer:

2x²-x+5=0

d=b²-4ac

d=(-x)²-4(2)(5)

d=x²-40

x=-b+(-)√b²-4ac/2a

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Answer 2

Answer:

[1 ± i√39] / 4

Step-by-step explanation:

x = [-b±√b² - 4ac] / 2a

x = 1 ± √1 - 40/4

  = 1 ±√-39 / 4

  = [1 ± i√39] / 4

   =