Question

2x^2+x-528=0
Find the roots

Answer 1

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Answer 2

Answer:

$-\frac{33}{2} ,\: 16\: are \\</p><p>roots \: of \: given \: quadratic\\equarion$

Step-by-step explanation:

$Given \: quadratic \: equation:\\2x^{2}+x-528=0$

Splitting the middle term, we get

$\implies 2x^{2}+33x-32x-528=0$

$\implies 2x^{2}+33x-16×2x-16×33=0$

$\implies x(2x+33)-16(2x+33)=0$

$\implies (2x+33)(x-16)=0$

$\implies (2x+33)=0\:Or\:x -16=0$

$\implies 2x=-33\:Or\:x=16$

$\implies x=-\frac{33}{2}\:Or\:x=16$

Therefore,

$-\frac{33}{2} ,\: 16\: are \\</p><p>roots \: of \: given \: quadratic\\equarion$

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