Question

2x^2+x-528 split the middle term

Answer 1

Answer:

Given : $2x^2+x-528$

To Find : split the middle term

Solution:

$2x^2+x-528$

Split the middle term i.e.x

$2x^2-32x+33x-528$

$2x(x-16)+33(x-16)$

$(x-16)(2x+33)$

Hence the middle term split of $2x^2+x-528$ is $2x^2-32x+33x-528$

Answer 2

Answer:

$2x^{2}+x-528=(2x+33)(x-16)$

Step-by-step explanation:

$Given \: Quadratic\: expression:\\2x^{2}+x-528$

/* Splitting the middle term,we get*/

$=2x^{2}+33x-32x-528\\=2x^{2}+33x-2x\times 16-33\times 16\\=x(2x+33)-16(2x+33)\\=(2x+33)(x-16)$

Therefore,

$2x^{2}+x-528=(2x+33)(x-16)$

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