Math, asked by param812, 7 months ago

2x^2-x-6=0 by completing the square method and quadratic formula​

Answers

Answered by inbisatpervez
1

Step-by-step explanation:

2x^2-4x+3x-6=0

(2x^2-4x)+(3x-6)=0

2x(x-2)+3(x-2)=0

(x-2)(2x+3)=0

x-2=0,2x+3=0

x=2,x=-3/2

by quadratic formula

x=-b+-square root (b^2-4ac)/2a

x=+1+-square root (1-4×2×-6)/2×2

x=+-sqaure root (1+48)/4

x=+-7/4

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