2x ² + x - 6=0 by factorisation method
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Answer:
2x²+x−6=0
2x²+4x−3x−6=0
2x(x+2)−3(x+2)=0
(2x−3)(x+2)=0
x=3/2;−2
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2x^2 + x - 6 = 0
Sum = 1
Product= -12
So ,
=> 2x^2 -3x + 4x - 12 = 0
=> x ( 2x - 3 ) + 2 ( 2x - 3 ) = 0
=> ( x + 2 ) ( 2x - 3 ) = 0
=> x = -2 or x = 3 / 2
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