Question

-2x^2+x+6=0 find x ?

Answer 1

Answer:

-2x²+x+6=0

-2x²+4x-3x+6=0

-2x(x+2)-3(x+2)=0

(-2x-3)(x+2)=0

-1(2x+3)(x+2)=0

(2x+3)(x+2)=0

x=-3/2,-2

Answer 2

Answer:

x=2 , -3/2

Step-by-step explanation:

-2x^2+x+6=0

taking, (-)negative sign common

2x^2-x-6=0

Now split the equation

2x^2-4x+3x-6=0

2x(x-2)+3(x-2)

(2x+3)(x-2)=0

Equating this with 0 we get two value of x=2, -3/2