Question

2x^2+x-6=0 solved by completing the square​

Answer 1

Answer:

x={1.5,-2}

Step-by-step explanation:

$2x^2+x-6=0\\\implies x^2+\frac{x}{2}-3=0\\\\\implies x^2+\frac{x}{2}=3\\\\\implies x^2+\frac{x}{2}+(\frac{1}{4})^2=3+(\frac{1}{4})^2\\\\\implies x^2+2(\frac{1}{4})(x)+(\frac{1}{4})^2=3+\frac{1}{16}\\\\\implies (x+\frac{1}{4})^2=\frac{48+1}{16}\\\\\implies x+\frac{1}{4}=\sqrt{\frac{49}{16}}\\\\\implies x+\frac{1}{4}=\pm\frac{7}{4}\\\\\implies x=\pm\frac{7}{4}-\frac{1}{4}\\\\\implies x=\{\frac{6}{4},\frac{-8}{4}\}\\\\\implies x=\{1.5,-2\}$

Hope it helps!

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