Question

2x^2+x-6


please help me with this​

Answer 1

Answer:

$\bf \small\underline \purple {Question :-}$

${2x}^{2} + x - 6$

$\bf \small\underline \purple{Required \: Answer :-}$

${2x}^{2} + x - 6$

${2x}^{2} + 4x - 3x - 6$

$2x(x + 2) - 3(x + 2)$

$(2x - 3)(x + 2)$

Finding zeros :-

Now let's find the first zero

$2x - 3 = 0$

$2x = 3$

$x = \frac{3}{2}$

We got our first zero as 3/2

Now let's find the second zero

$x + 2 = 0$

$x = - 2$

$\bf \small \therefore \:the \: two \: zeros \: are \: \frac{3}{2} \: and \: - 2$

Answer 2

Step-by-step explanation:

i hope it helps you complete