Math, asked by margajsiddhi3546, 10 months ago

2x^2+x+a is divided x-3 the remainder is 1 find the factors of 2x^2+x+a-1

Answers

Answered by bijaymourya8114
2

Answer:

p(x) =

2 {x}^{2}  + x + a \\

g(x) =

x - 3

r(x) =

1

Now divide p(x) by g(x)

we get r(x) = a+21

r(x) = 1 it is given. So,

=1=a+21

=a=-20

NOW,

p(x) = 0 \\ p(x) = 2 {x}^{2}  + x + a - 1 \\   = 2 {x}^{2}  + x  - 20 - 1 \\  = 2 {x}^{2}  + x - 21 \\  = 2 {x}^{2}  + 7x - 6x - 21 \\  = x(2x + 7) - 3(2x + 7)  \\   = (x - 3)(2x + 7) \\  = x = 3 \: or \:  - 7by \: 2

Answered by ITZMMEE
0

Answer:

this

Step-by-step explanation:

this

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