Math, asked by pranjal326620, 2 months ago

(2x^-2 y^3)3
can anyone help me?

Answers

Answered by Acatalepsy
40

\bf\underline{\underline{˙❥˙solution:}}

( {{2x}^{ - 2}  \times  {y}^{3}})^{3}

 {(( \frac{ {1}^{2} }{2x})  \times  {y}^{3}) }^{3}

 {( \frac{1}{ {4x}^{2} }  \times  {y}^{3})}^{3}

reciprocating~

 \frac{1}{64 {x}^{6} }  \times  {y}^{9}

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