Question

2x^+2x-289 =0 find the roots​

Answer 1

Answer:

I'm assuming the question is supposed to be find the roots​ of 2x^2 +2x-289 =0

a=2 , b=2 , c=-289

By using the quadratic formula,

x= (-2± sq root( 2^2- *4*2*(-289)))/2*2

x= -1± sq root (579)

And that is the answer, hope that helps