Question

2x(2x+3+x)
solve this​

Answer 1

Answer:

Step-by-step explanation:

$2x(2x+3+x)$

$4x^{2} +6x+2x^{2}=0$

$6x^{2} +6x=0$

$6x(x+1)=0$

$x+1=0$

$x=-1$

Answer 2

In accordance with the information provided in the question,

We have find the value of the supplied expression in the above question.

Given the data in question 2x(2x+3+x)=0

We have find the value of given expression and we have find the value of x

So, we will multiply of 2x and find the value of x

AS we get ,

$2x(2x+3+x)=0\\=4x^{2} +6x+2x^{2}=0 \\=6x^{2} +6x=0\\=6x(x+1)=0\\=x+1=0\\x=-1$

Hence the solution will be $x=-1$.