Question

2x^2y+2xy^2+xy when x=0, y=-1​

Answer 1

Answer:

2x^2y+2xy^2+xy

x=0, y=-1

putting value of x and y

2(0)^2(-1)+2(0)(-1)^2+(0)(-1)

0+0+0

0

Answer is 0

Answer 2

Answer:

2×0^-1+2×(-1)×0^2+0+(-1)

-1