Math, asked by HANSINEEMANGALAM, 3 months ago

2x^3 +1/(x - 1)(x +1)(x+2)=

1) 2+ 1/2(x-1) + 1/2(x+1) - 15/(x+2)

2) 2-1/1(x-1) - 1/2(x+1) - 15/x+2

3) 2+1/2(x-1) - 1/2(x+1) - 15/x+2

4) 1/2(x-1) + 1/2(x+1) - 15/x+2

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Answered by akshitkumarsingh1234

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Answered by kridhiya1997

Answer: HERE IS YOUR ANSWER....

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2x^3 +1/(x - 1)(x +1)(x+2)=1) 2+ 1/2(x-1) + 1/2(x+1) - 15/(x+2)2) 2-1/1(x-1) - 1/2(x+1) - 15/x+23) 2+1/2(x-1) - 1/2(x+1) - 15/x+24) 1/2(x-1) + 1/2(x+1) - 15/x+2​

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2x^3 +1/(x - 1)(x +1)(x+2)=

1) 2+ 1/2(x-1) + 1/2(x+1) - 15/(x+2)

2) 2-1/1(x-1) - 1/2(x+1) - 15/x+2

3) 2+1/2(x-1) - 1/2(x+1) - 15/x+2

4) 1/2(x-1) + 1/2(x+1) - 15/x+2