2x^3+10x^2+5x+25 and x^3+5x^2-x-5
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If you want to divide these two,
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(2x³ +10x² +5x +25) ÷ x³ + 5x² -x -5,
You can factorise 2x³ +10x² +5x +25 as (x+5)(2x²+5) and x³ + 5x² -x -5 as (x+5)(x²+5) .
So it cancels out (x+5) term and you're left with:
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