2x-3=1then value of x is
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Given Equation is 2^x-3 = 1.
Apply log on both sides, we get
log(2^x-3) = log 1
We know that log(x^b) = b.log(x)
(x - 3)log 2 = log 1
We know that log 1 = 0
(x - 3) log 2 = 0
(x - 3) = 0/log 2
x - 3 = 0
x = 3.
Hope this helps!
Apply log on both sides, we get
log(2^x-3) = log 1
We know that log(x^b) = b.log(x)
(x - 3)log 2 = log 1
We know that log 1 = 0
(x - 3) log 2 = 0
(x - 3) = 0/log 2
x - 3 = 0
x = 3.
Hope this helps!
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