Question

(2x+3)^2=25 by formula method

Answer 1

$\huge\boxed{\fcolorbox{blue}{orange}{HELLO\:MATE}}$

GIVEN:

$(2x+3) ^{2}=25$

TO FIND:

The value of x.

SOLUTION:

=>$(2x+3) ^{2}=25$

=>$(2x+3) ^{2}=5^{2}$

Eliminating squares both sides,

=>$2x+3=5$

=>$2x = 5-3$

=>$2x = 2$

=>$x =\dfrac{2}{2}$

=>$x =1$

Therefore the value of x is 1.

$\huge\orange{\boxed{x=1}}$

Answer 2

$\blue{\bold{\underline{\underline{Answer:}}}}$

$\green{\tt{\therefore{Value\:of\:x=1\:and\:-4}}}$

$\orange{\bold{\underline{\underline{Step-by-step\:explanation:}}}}$

$\green{\underline \bold{Given :}} \\ \tt: \implies {(2x + 3)}^{2} = 25 \\ \\\red{\underline \bold{To \: Find:}} \\ \tt: \implies Value \: of \: x = ?$

• According to given question :

$\tt: \implies {(2x + 3)}^{2} = 25 \\ \\ \tt \circ \: (a + b)^{2} = {a}^{2} + {b}^{2} + 2ab \\ \\ \tt: \implies 4 {x}^{2} + 9 + 12x = 25 \\ \\ \tt: \implies 4 {x}^{2} + 9 + 12x - 25 = 0 \\ \\ \tt: \implies 4 {x}^{2} + 12x - 16 = 0 \\ \\ \tt: \implies {x}^{2} + 3x - 4 = 0 \\ \\ \bold{As \: we \: know \: that} \\ \tt: \implies {x}^{2} + 4x - x - 4 = 0 \\ \\ \tt: \implies x(x + 4) - 1(x + 4) = 0 \\ \\ \tt: \implies (x - 1)(x + 4) = 0 \\ \\ \green{\tt: \implies x = 1 \: and \: - 4}$