Question

(2x+3)2=25 quadratic equations ax2+bx+c=0find the values a,b,c,
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Answer 1

Answer:

2a+b=4

c=-19

but I got data is incorrect

Answer 2

$\\ \sf\longmapsto (2x+3)^2=25$

$\boxed{\sf (a+b)^2=a^2+2ab+b^2}$

$\\ \sf\longmapsto 2x^2+2\times 2x\times 3+ 3^2=25$

$\\ \sf\longmapsto 4x^2+12x+9=25$

$\\ \sf\longmapsto 4x^2+12x+9-25=0$

$\\ \sf\longmapsto 4x^2+12x-16=0$

$\\ \sf\longmapsto 4(x^2+3x-4=0)$

$\\ \sf\longmapsto x^2+3x-4=0$

• Comparing with ax^2+bx+c=0

$\\ \sf\longmapsto a=1$

$\\ \sf\longmapsto b=3$

$\\ \sf\longmapsto c=-4$