2x-3/2x+1=3x+1/3x-1
i don't understand pls help
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Answered by
0
Solution
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Given
(2x−1)
(2x−3)
=
(3x+1)
(3x−1)
(2x−3)(3x+1)=(3x−1)(2x−1)
On further calculations , we get ,
6x
2
+2x−9x−3=6x
2
−3x−2x+1
6x
2
−7x−3=6x
2
−5x+1
6x
2
−7x−6x
2
+5x=1+3
−7x+5x=4
−2x=4
We get ,
x=
−2
4
x=−2
verified
Verified by Toppr
Given
(2x−1)
(2x−3)
=
(3x+1)
(3x−1)
(2x−3)(3x+1)=(3x−1)(2x−1)
On further calculations , we get ,
6x
2
+2x−9x−3=6x
2
−3x−2x+1
6x
2
−7x−3=6x
2
−5x+1
6x
2
−7x−6x
2
+5x=1+3
−7x+5x=4
−2x=4
We get ,
x=
−2
4
x=−2
Answered by
0
Step-by-step explanation:
Given
(2x−1)
(2x−3)
=
(3x+1)
(3x−1)
(2x−3)(3x+1)=(3x−1)(2x−1)
On further calculations , we get ,
6x
2
+2x−9x−3=6x
2
−3x−2x+1
6x
2
−7x−3=6x
2
−5x+1
6x
2
−7x−6x
2
+5x=1+3
−7x+5x=4
−2x=4
We get ,
x=
−2
4
x=−2
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