2x-3/2x-1=3x-1/3x+1
It is very difficult to do because when I do the answer it is different from my book answer my answer is x = 1/-2
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(2x-3)/(2x-1)=(3x-1)/(3x+1)
(2x-3)(3x+1) = (3x-1)(2x-1)
(6x^2+2x-9x-3) = (6x^2-3x-2x+1)
6x^2+7x-3 = 6x^2-5x+1
6x^2+7x-3-6x^2+5x-1 =0
12x-4= 0
12x=4
X=4/12
X=1/3
this is your answer.......
(2x-3)(3x+1) = (3x-1)(2x-1)
(6x^2+2x-9x-3) = (6x^2-3x-2x+1)
6x^2+7x-3 = 6x^2-5x+1
6x^2+7x-3-6x^2+5x-1 =0
12x-4= 0
12x=4
X=4/12
X=1/3
this is your answer.......
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