Question

2x-3=√2x^2-2+21x factorise​

Answer 1

SOLUTION

$= > 2x - 3 = \sqrt{ {2x}^{2} - 2x + 21} \\ = > 2x - 3 = (2x {}^{ \frac{1}{2} } {x}^{2} ) - 2x + 21 \\ = > 2x - 3 = 2x - 2x + 21 \\ = > 2x - 3 = 21 \\ = > 2x = 21 + 3 \\ = > x = \frac{24}{2} \\ \\ = > x = 12$

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Answer 2

Step-by-step explanation:

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