Question

(2x+ 3)×(2x-3)×(4x's square-9)​

Answer 1

Answer:

ans 15

Step-by-step explanation:

2x+ 3)×(2x-3)×(4x's square-9)2x+ 3)×(2x-3)×(4x's square-9) 2x+ 3)×(2x-3)×(4x's square-9) hi good morning how are you have a nice day 2x+ 3)×(2x-3)×(4x's square-9)2x+ 3)×(2x-3)×(4x's square-9)

Answer 2

Answer:

a) 16x^4 - 72x^2 +81. a) b^2-36

$(a + b)(a - b) = {a}^{2} - b {}^{2}$

Step-by-step explanation:

a). [(2x)^2-(3)^2] × (4x^2-9). { by using this formula

= ( a+b) × (a-b) = a^2 - b^2... here a=2x and. b= 3 }

= (4x^2-9) × (4x^2-9)

= 4x^2 ×4x^2 - 9 × 4x^2 - 4x^2 × 9 + 9×9

= 16x^4-36x^2 - 36x^2 + 81

= 16x^4 -72x^2 +81

a) {again using that formula (a+b)×(a-b)=a^2-b^2}. =b^2 -36