Question

2x-3(2x+3)/7x+(3+4x)=7/6​

Answer 1

The value of x is $-\frac{75}{101}$

Step-by-step explanation:

Given : Expression  $\frac{2x-3(2x+3)}{7x+(3+4x)}=\frac{7}{6}$

To find : Simplify the expression ?

Solution :

$\frac{2x-3(2x+3)}{7x+(3+4x)}=\frac{7}{6}$

Opening the brackets,

$\frac{2x-6x-9}{7x+3+4x}=\frac{7}{6}$

$\frac{-4x-9}{11x+3}=\frac{7}{6}$

Cross multiply,

$6(-4x-9)=7(11x+3)$

$-24x-54=77x+21$

$-24x-77x=21+54$

$-101x=75$

$x=-\frac{75}{101}$

Therefore, the value of x is $-\frac{75}{101}$

#Learn more

What is the answer to

4x-3 = 2x+7

and

2x+6 = 7x-14

https://brainly.in/question/13474677

Answer 2

Step-by-step explanation:

open the image this may be helpful