Question

(2x+3) (2x+5) (x-1) (x-2)=30​

Answer 1

$\huge\red\boxed{{Answer}}$

$(2x + 3)(2x + 5)(x + 1)(x -1) = 0$

$2x (2x + 5) + 3(2x + 5)x(x - 1) + 1(x - 1) = 30$

$(4x + 10x + 6x + 15x)( {x }^{2} - x + x - 1) = 0$

$35x(x - 1) = 30$

$35 {x}^{2} - 35x = 30$

${x}^{2} - 35x = \frac{30}{35}$

${x}^{2} - x = 35 \times \frac{6}{7}$

$x = 30$