Question

2x-3=3/10(5x-12)solve this equation​

Answer 1

$\huge\bold{\gray{\sf{Answer:}}}$

$\bold{Explanation:}$

$\sf 2x - 3 = \dfrac{3}{10} (5x - 12)$

$\sf= > 10(2x - 3) = 3(5x - 12)$

$\sf= > 20x - 30 = 15x - 36$

$\sf= > 20 - 15x = - 36 + 30$

$\sf= > 5x = - 6$

$\bold{\red{x = - \dfrac{6}{5}}}$

Check:-

Taking LHS

$2 \times - \dfrac{6}{5} - 3$

$\sf= > - \dfrac{12}{5} - 3 = \dfrac{ - 12 - 15}{5} = - \dfrac{27}{5}$

Taking RHS

$\sf= > \dfrac{3}{10} (5 \times - \dfrac{6}{5} - 12)$

$\sf= > \dfrac{3}{10} ( - 6 - 12)$

$\sf= > - 18 \times \dfrac{3}{10} = - 9 \times \dfrac{3}{5} = - \dfrac{27}{5}$

$\therefore$LHS=RHS

Answer 2

Answer:

$\bf {x = \frac {-6}{5} }$ is Your Answer

Step-by-step explanation:

$\huge{ \boxed{ \boxed{ \underline{ \underline{ \textsf{ \textbf{Question }}}}}}}$

• $\sf {2x -3 = \frac{3}{10}(5x-12)}$

$\huge{ \boxed{ \boxed{ \underline{ \underline{ \textsf{ \textbf{SolutioN }}}}}}}$

• $\sf {2x -3 = \frac{3}{10}(5x-12)}$

• Bring 10 to the left side

• $\sf {10(2x -3) = 3(5x - 12)}$

• $\sf {20x - 30 = 15x - 36)}$

• Now, bring 15x to left side

• $\sf {20x - 15x = 30 - 36}$

• $\sf {5x = -6}$

• $\bf {x = \frac {-6}{5} }$

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