Question

(2x/3-3/2x-1)^2
please....

Answer 1

Answer:

Given

(2x−1)

(2x−3)

=

(3x+1)

(3x−1)

(2x−3)(3x+1)=(3x−1)(2x−1)

On further calculations , we get ,

6x

2

+2x−9x−3=6x

2

−3x−2x+1

6x

2

−7x−3=6x

2

−5x+1

6x

2

−7x−6x

2

+5x=1+3

−7x+5x=4

−2x=4

We get ,

x=

−2

4

x=−2

Answer 2

Answer:

$( \frac{ - 5x - 6}{6} ) {}^{2}$

is your answer

hope it helps