Question

2x-3/35-1/10=4-3x/28​

Answer 1

Step-by-step explanation:

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2x-1 \cdot \frac{3}{35}-1 \cdot \frac{1}{10}=4-1 \cdot \frac{3x}{28}

2x−1⋅353−1⋅101=4−1⋅283x

Solve

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Multiply the numbers

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2x{\color{#c92786}{-1}} \cdot {\color{#c92786}{\frac{3}{35}}}-1 \cdot \frac{1}{10}=4-1 \cdot \frac{3x}{28}

2x−1⋅353−1⋅101=4−1⋅283x

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2x{\color{#c92786}{-\frac{3}{35}}}-1 \cdot \frac{1}{10}=4-1 \cdot \frac{3x}{28}

2x−353−1⋅101=4−1⋅283x

2

Answer 2

$\huge {\boxed {\mathbb {QUESTION}}}$

$\frac{2x-3}{35}-\frac{1}{10}=\frac{4-3x}{28}$

$\huge {\boxed {\mathbb {ANSWER}}}$

$\implies \frac{2x-3}{35}-\frac{1}{10}=\frac{4-3x}{28}$

$\implies \frac{4x-6-7}{70}=\frac{4-3x}{28}$

$\implies \frac{4x-13}{70}=\frac{4-3x}{28}$

$\implies 28(4x-13)=70(4-3x)$

$\implies 112x-364=280-210x$

$\implies 112x+210x=280+362$

$\implies 322x=644$

$\implies x=\frac{644}{322}$

$\implies {\boxed {\boxed {x=2}}}$

$\huge {\boxed {\mathbb {HOPE \:IT \:HELPS \:YOU}}}$

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$Identities$

${(a+b)}^{2}={a}^{2}+2ab+{b}^{2}$

${(a-b)}^{2}={a}^{2}-2ab+{b}^{2}$

$(a+b) (a-b) ={a}^{2}-{b}^{2}$

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