Question

(2x + 3) (3x - 1)=​

Answer 1

Step-by-step explanation:

$(2x + 3)(3x - 1) \\ \\ 2x(3x - 1) + 3(3x - 1) \\ \\ 6 {x}^{2} - 2x + 9x - 3 \\ \\ 6 {x}^{2} + 7x - 3 = 0 \\ \\ 6 {x}^{2} + 9x - 2x - 3 = 0 \\ \\ 3x(2x + 3) - 1(2x + 3) = 0\\ \\ (3x - 1)(2x + 3) = 0 \\ \\ x = \frac{1}{3} ........x = \frac{ - 3}{2}$

hope it helps......

mark it as brainliest.....

Answer 2

Answer:

(2x + 3) (3x - 1)

= 2x( 3x -1) +3(3x-1)

= 6x² - 2x + 9x - 3

= 6x² + 7x -3

This is quadratic equation

6x² + 7x -3 = 0

6x² + 9x - 2x -3 =0

3x(2x + 3) -1(2x + 3)= 0

( 2x+3) (3x -1) = 0

2x + 3 = 0 or 3x - 1=0

2x = -3 or 3x =1

x = -3 / 2 or x = 1/3