Question

2x^3-3x^2+7x-8 is divided by x-1​

Answer 1

Answer:

x-1)2x^3 - 3x^2 + 7x - 8(2x^2 - 5x + 2

- 2x^3 + 2x^2

-5x^2+7x

- (5x^2)+ 5x

2x - 8

- 2x - 2

-6

Answer 2

$\Large{\underline{\underline{\bf{Solution :}}}}$

(x - 1) = 0

x = 1

Put Value of x in the polynomial.

$\sf{2(1)^3 - 3(1)^2 + 7(1) - 8} \\ \\ \sf{→2 - 3 + 7 - 8} \\ \\ \sf{→11 - 11} \\ \\ \sf{→0}$