2x^3-3x^2-x-1=0 find factors
Answers
Answer:
2x3-3x2-x=0
Three solutions were found :
x =(3-√17)/4=-0.281
x =(3+√17)/4= 1.781
x = 0
Step by step solution :
Step 1 :
Equation at the end of step 1 :
((2 • (x3)) - 3x2) - x = 0
Step 2 :
Equation at the end of step 2 :
(2x3 - 3x2) - x = 0
Step 3 :
Step 4 :
Pulling out like terms :
4.1 Pull out like factors :
2x3 - 3x2 - x = x • (2x2 - 3x - 1)
Trying to factor by splitting the middle term
4.2 Factoring 2x2 - 3x - 1
The first term is, 2x2 its coefficient is 2 .
The middle term is, -3x its coefficient is -3 .
The last term, "the constant", is -1
Step-1 : Multiply the coefficient of the first term by the constant 2 • -1 = -2
Step-2 : Find two factors of -2 whose sum equals the coefficient of the middle term, which is -3 .
-2 + 1 = -1
-1 + 2 = 1
Observation : No two such factors can be found !!
Conclusion : Trinomial can not be factored
Equation at the end of step 4 :
x • (2x2 - 3x - 1) = 0
Step-by-step explanation: