2x-3/3x-5=5/7
Dolve this linear equ
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Answer:
Equation \frac{x+3}{7}-\frac{2x-5}{3}=\frac{3x-5}{5}-257x+3−32x−5=53x−5−25
Taking LCM,
\frac{3(x+3)-7(2x-5)}{21}=\frac{3x-5-125}{5}213(x+3)−7(2x−5)=53x−5−125
\frac{3x+9-14x+35}{21}=\frac{3x-5-125}{5}213x+9−14x+35=53x−5−125
\frac{-11x+44}{21}=\frac{3x-130}{5}21−11x+44=53x−130
Cross multiply,
5(-11x+44)=21(3x-130)5(−11x+44)=21(3x−130)
-55x+220=63x-2730−55x+220=63x−2730
63x+55x=2730+22063x+55x=2730+220
118x=2950118x=2950
x=\frac{2950}{118}x=1182950
x=25x=25
Therefore, The value of x is 25
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