Question

(2x÷3-3y÷2)² please give me the answer its important​

Answer 1

Answer:

(2x÷3-3y÷2)^2

4x^2×1/9-9y^2×1/4

x^2×1/9-9y^2×1

x^2/9-9y^2

(x^2-81y^2)/9

x^2-81y^2=9

Answer 2

Step-by-step explanation:

use identity (a - b)² = a² - 2ab + b²

${( \frac{2x}{3} - \frac{3y}{2}) }^{2} \\ = {( \frac{2x}{3}) }^{2} - 2( \frac{2x}{3})( \frac{3y}{2} ) + ({ \frac{3y}{2} )}^{2} \\ = \frac{4 {x}^{2} }{9} - 2xy + \frac{9 {y}^{2} }{4}$

Hope you get your answer