Question

2x-3/4x+3=3x+2/7x+18, solve using quadratic equation.​

Answer 1

Answer:

$\frac{2x - 3}{4x + 3} = \frac{3x + 2}{7x + 18} \\ \\ (3x + 2)(4x + 3) = (2x - 3)(7x + 18) \\ \\ {12x}^{2} + 9 + {8x}^{2} + 6 = {14x}^{2} + 36 - 21x - 54 \\ \\ 27x = - 33 \\ \\ x = \frac{27}{ - 33} \\ \\ x = \frac{ - 11}{7}$

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