2x^3-5x^2-14x+8 factorise
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Answered by
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The factorization of (2x³ - 5x² - 14x + 8) is (x + 2)(x - 4)(2x - 1)
Step-by-step explanation:
We have to factorize the following cubic expression.
It is 2x³ - 5x² - 14x + 8
Now, the expression vanishes to become zero if we put x = - 2
So, (x + 2) will be a factor of the expression.
Now, 2x³ - 5x² - 14x + 8
= 2x³ + 4x² - 9x² - 18x + 4x + 8
= 2x²(x + 2) - 9x(x + 2) + 4(x + 2)
= (2x² - 9x + 4)(x + 2)
= (x + 2)(2x² - 8x - x + 4)
= (x + 2)[2x(x - 4) - 1(x - 4)]
= (x + 2)(x - 4)(2x - 1)
Therefore, the factorization of (2x³ - 5x² - 14x + 8) is (x + 2)(x - 4)(2x - 1)(Answer)
Answered by
3
Answer:
so the answer is x=-2 , x=4 , x=1/2
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