Question

2x+3/6x-7=4/6x.....
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Answer 1

$\frac{2x + 3}{6x - 7} = \frac{4}{6x} \\ \\ 6x(2x + 3) = 4(6x - 7) \\ \\ 6x \times 2x + 6x \times 3 = 4 \times 6x - 4 \times 7 \\ \\ 12 {x}^{2} + 18x = 24x - 28 \\ \\ 12 {x}^{2} + 18x - 24x + 28 = 0 \\ \\ 12 {x}^{2} - 6x + 28 = 0 \\ \\ 6 {x}^{2} - 3x + 14 = 0 \\ \\ x = \frac{3 + \sqrt{9 - 4 \times 6 \times 14} }{2 \times 6} \\ \\ x = \frac{3 + \sqrt{ - 327} }{12} \\ \\ x = \frac{3 + \sqrt{327} i}{12} \\ \\ or \\ \\ x = \frac{3 - \sqrt{327}i }{12} \\ \\ hope \: \: \: it \: \: \: helps \: \: \: to \: \: \: u$

Answer 2

Answer:

$\begin{gathered} \frac{2x + 3}{6x - 7} = \frac{4}{6x} \\ \\ 6x(2x + 3) = 4(6x - 7) \\ \\ 6x \times 2x + 6x \times 3 = 4 \times 6x - 4 \times 7 \\ \\ 12 {x}^{2} + 18x = 24x - 28 \\ \\ 12 {x}^{2} + 18x - 24x + 28 = 0 \\ \\ 12 {x}^{2} - 6x + 28 = 0 \\ \\ 6 {x}^{2} - 3x + 14 = 0 \\ \\ x = \frac{3 + \sqrt{9 - 4 \times 6 \times 14} }{2 \times 6} \\ \\ x = \frac{3 + \sqrt{ - 327} }{12} \\ \\ x = \frac{3 + \sqrt{327} i}{12} \\ \\ or \\ \\ x = \frac{3 - \sqrt{327}i }{12} \\ \\ hope \: \: \: it \: \: \: helps \: \: \: to \: \: \: u\end{gathered}6x−72x+3=6x46x(2x+3)=4(6x−7)6x×2x+6x×3=4×6x−4×712x2+18x=24x−2812x2+18x−24x+28=012x2−6x+28=06x2−3x+14=0x=2×63+9−4×6×14x=123+−327x=123+327iorx=123−327ihopeithelpstou$

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