2x-3/9+x+3/4=4x+1/7
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\qquad -5(x+3)>2x+7+5x .... \gray{\text{multiplying by }\dfrac{-1}{-1}} ..... \qquad = \ left( {\dfrac{1}{2}x} {-1}\right) (x^3+2x^2+4x+8) ...... \qquad \dfrac{2x(x+2)}{x(x-4)(x- 1)} \div \dfrac{\red{4(x-2)(x+2)}}{\blue{(x-2)(x-4)}}
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