Question

(2x-3) dx/root 2x-6x+1

Answer 1

hello users .....

solution:-
please see the attachment...

hence;
Integration of (2x -3).dx / √(2x² -6x + 1 ) is equal to √(2x² -6x +1) + C Answer

⭐ hope it helps ⭐

Answer 2

Hey!!
§ (2x-3)/√(2x²-6x+1) dx

Now put 2x²-6x+1 = t
we get 4x-6 dx = dt
2(2x-3) dx = dt
(2x-3)dx = 1/2dt

=> 1/2§ dt/√t
=> 1/2 § t^-1/2
=> 1/2 × t^ -1/2+1/-1/2+1 + C
=> √t + c
Plug in the value of t we get

§ (2x-3)/√(2x²-6x+1) dx = √2x²-6x+1 + C