(2x-3) dx/root 2x-6x+1
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hello users .....
solution:-
please see the attachment...
hence;
Integration of (2x -3).dx / √(2x² -6x + 1 ) is equal to √(2x² -6x +1) + C Answer
⭐ hope it helps ⭐
solution:-
please see the attachment...
hence;
Integration of (2x -3).dx / √(2x² -6x + 1 ) is equal to √(2x² -6x +1) + C Answer
⭐ hope it helps ⭐
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Anonymous:
perfect
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Hey!!
§ (2x-3)/√(2x²-6x+1) dx
Now put 2x²-6x+1 = t
we get 4x-6 dx = dt
2(2x-3) dx = dt
(2x-3)dx = 1/2dt
=> 1/2§ dt/√t
=> 1/2 § t^-1/2
=> 1/2 × t^ -1/2+1/-1/2+1 + C
=> √t + c
Plug in the value of t we get
§ (2x-3)/√(2x²-6x+1) dx = √2x²-6x+1 + C
§ (2x-3)/√(2x²-6x+1) dx
Now put 2x²-6x+1 = t
we get 4x-6 dx = dt
2(2x-3) dx = dt
(2x-3)dx = 1/2dt
=> 1/2§ dt/√t
=> 1/2 § t^-1/2
=> 1/2 × t^ -1/2+1/-1/2+1 + C
=> √t + c
Plug in the value of t we get
§ (2x-3)/√(2x²-6x+1) dx = √2x²-6x+1 + C
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