Question

√2x√3 का घातांक रुप क्या है

​

Answer 1

Answer:

$\sqrt{2 } \times \sqrt{3}$

$\sqrt{6}$

Answer 2

Answer:

Step-by-step explanation:

?kkrkad osQ fu;e

ge lh[k pqosQ gSa fd dksbZ Hkh 'kwU;srj ifjes; la[;k a osQ fy, a

m

× a

n = a

m + n

, tgk¡ m vkSj n

izko`Qr la[;k,¡ gS aA ;fn ?kkrkad Í.kkRed gS rks Hkh D;k ;g fu;e lR; gS\ gesa [kkstuk pkfg,A

(i) ge tkurs gSa fd 2 – 3 = 3

1

2

vkSj 2 – 2 = 2

1

2

vr%,

3 2 2 2 − − × = 3 2 3 2 3 2

1 1 1 1

2 2 2 2 2 +

× = = =

×

2 – 5

(ii) (–3)– 4 × (–3)–3 ysus ij

(–3)– 4 ×(–3)–3 = 4 3

1 1

( 3) ( 3)

×

− −

= 4 3 4 3

1 1

( 3) ( 3) ( 3) +

=

− × − −

= (–3)–7

(iii) vc 5–2 × 54 dks fyf[k,A

5

–2 × 54 =

4

4 4 2

2 2

1 5 5 5

5 5

−

× = = = 5(2)

(iv) vc (–5)– 4 × (–5)2 dks fyf[k,A

(–5)– 4 × (–5)2

=

2

2

4 4 4 2

1 ( 5) 1 ( 5)

( 5) ( 5) ( 5) ( 5)−

−

× − = =

− − − × −

= 4 2

1

( 5) −

−

= (–5)– (2)

lk/kj.kr;k ge dg ldrs gSa fd fdlh 'kwU;srj ifjes; la[;k a osQ fy,

a

m × a

n = a

m + n

, tgk¡ m vkSj n ifjes; la[;k,¡ gSaA