Question

2x/3<1 (linear inequality)

Answer 1

hope it helps!!!!!!!!!

Answer 2

$your \: question \: is \: = > \\ > > \: \frac{2}{3} x < 1 \\ now \: we \: put \: some \: value \: of \: x \: becoz \\ \: we \: have \: to \: show \: \frac{2}{3} x \: is \: smaller \: \\ than \: 1 \: so \\ if \: we \: will \: put \: the \: value \: of \ \\ x \: = - 3 \: then \\ \frac{2}{3} \times - 3 = \frac{ - 6}{3} = - 2 \: which \: is \: \\ smaller \: than \: 1$