2x^3+mx^2+11x+m+3 is exactly divisible by 2x-1. What is m?
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7
Answer:
-7
Step-by-step explanation:
p(x)= 2x³+mx²+11x+m+3
∴2x-1=0
⇒2x=1
⇒x=1/2
p(1/2)=2(1/2)³+m(1/2)²+11(1/2)+m+3 = 0 (as it is exactly divisible, we'd write
p(1/2)=0)
⇒p(1/2)= 2*1/8+ m/4 +11/2 + m + 3 = 0
⇒p(1/2= 1/4+m/4+11/2+m= -3
⇒p(1/2)= m/4 + m= -3 -11/2 -1/4
⇒p(1/2) = m+4m/4 = -12/4 - 22/4 -1/4
⇒p(1/2) = 5m/4= -35/4
⇒p(1/2)= m = -35/4*4/5
∴m=-7
Therefore, m = -7
I hope it'll help you. Have good day :)
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