√2x+3-√x+1=1 solve it!!!!
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Answer:
Solution: x=−1,3
Explanation:
The strategy with solving radical equations is to use the "isolate and square" method on each radical, one at a time.
Step 1: Isolate √2x+3 on the left side of the equation.
√2x+3=√x+1+1
Step 2: Square both sides of the equation.
(√2x+3)2=(√x+1+1)2
2x+3=x+2+2√x+1
Step 3: Isolate √2x+3 on the right side of the equation.
x+1=2√x+1
Step 4: Square both sides of the equation.
(x+1)2=(2√x+1)2
x2+2x+1=4(x+1)
x2−2x−3=0
(x−3)(x+1)=0
x=−1,3
Solution: x=−1,3
Explanation:
The strategy with solving radical equations is to use the "isolate and square" method on each radical, one at a time.
Step 1: Isolate √2x+3 on the left side of the equation.
√2x+3=√x+1+1
Step 2: Square both sides of the equation.
(√2x+3)2=(√x+1+1)2
2x+3=x+2+2√x+1
Step 3: Isolate √2x+3 on the right side of the equation.
x+1=2√x+1
Step 4: Square both sides of the equation.
(x+1)2=(2√x+1)2
x2+2x+1=4(x+1)
x2−2x−3=0
(x−3)(x+1)=0
x=−1,3
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