India Languages, asked by yaashhh24, 10 months ago

(2x^3+x^2+3)/(x^2+2)^2 லிருந்து 1/(x^2+2) ஐ கழிக்க

Answers

Answered by naveenrishi12798
0

Answer:

சொற்றொடர்கள் 2+3=சொற்றொடர்கள்

Answered by steffiaspinno
0

கழிக்க \frac{2 x^{3}+x^{2}+2}{\left(x^{2}+2\right)^{2}}-\frac{1}{x^{2}+2}  

தீர்வு:  

கொடுக்கப்பட்டது \frac{2 x^{3}+x^{2}+2}{\left(x^{2}+2\right)^{2}}-\frac{1}{x^{2}+2}

மீ.பொ.ம \left(x^{2}+2\right)^{2}

\frac{2 x^{3}+x^{2}+3-\left(x^{2}+2\right)}{-\left(x^{2}+2\right)^{2}}  

\frac{2 x^{3}+x^{2}+3-x^{2}+2}{\left(x^{2}+2\right)^{2}}

\frac{2 x^{3}+3-2}{\left(x^{2}+2\right)^{2}}  

\frac{2 x^{3}+1}{\left(x^{2}+2\right)^{2}}  

விடை: \frac{2 x^{3}+1}{\left(x^{2}+2\right)^{2}}  

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