Question

(2x+3) (x-4) =6
quadratic equation
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Answer 1

♡ Answer ♡

$\\ \\ (2x+3) (x-4) =6 \\ \implies(2x²-8x+3x - 12) =6 \\ \implies2x²-5x - 12 - 6= 0 \\ \implies2x²-5x - 18 = 0 \\ \implies2x {}^{2} - (9 - 4)x - 18 = 0 \\ \implies2x {}^{2} - 9x + 4x - 18 = 0 \\ \impliesx (2x - 9) + 2(2x - 9) = 0 \\ \implies(2x - 9)(x + 2) = 0$

Answer 2

(2x+3) (x-4) =6

2x²-8x+3x-12=6

2x²-5x-12-6=0

2x²-5x-18=0.

2x²-(9-4)x-18=0

2x²-9x+4x-18=0

x(2x-9)+2(2x-9)=0

(x+2)(2x-9)=0

:.x+2=0

x=-2

:.2x-9=0

or, 2x=9

x=9/2