(2x+3) (x-4)=6 solve the equation
Answers
Answered by
35
ans
(2x+3)(X-4)=6
2x(x-4)+3(x-4)=6
2x^2-8x+3x-12=6
2x^2-5x-18=0
2x^2-(9-4)x-18=0
2x^2-9x+4x-18=0
X(2x-9)+2(2x-9)=0
X=-2,X=9/2
(2x+3)(X-4)=6
2x(x-4)+3(x-4)=6
2x^2-8x+3x-12=6
2x^2-5x-18=0
2x^2-(9-4)x-18=0
2x^2-9x+4x-18=0
X(2x-9)+2(2x-9)=0
X=-2,X=9/2
Answered by
26
hope this helps you....✌✌
Attachments:
DeeptiMohanty:
stop this
Similar questions