[(2x+3)+(x+5)]°2 + [(2x+3)-(x+5)]°2 =10x°2 +92
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Answer:
x = 6/11
Step-by-step explanation:
[(2x+3)+(x+5)]^2 + [(2x+3)-(x+5)]^2 =
10x^2 + 92
(3x+8)^2 + (x-2)^2 = 10x^2 + 92
9x^2+64+48x+x^2+4-4x = 10x^2 + 92
10x^2+44x+68 = 10x^2+92
10x^2-10x^2+44x = 92-68
44x = 24
x = 24/44
x = 6/11
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