Question

[ (2x+3)+(x+5)]^2 +[(2x+3)-(x+5)]^2 =10x^2 +92​

Answer 1

Answer:

6/11

Step-by-step explanation:

(2x+3+x+5)^2+(2x+3-x-5)^2=10x^2+92

(3x+8)^2+(x-2)^2=10x^2+92

(3x)^2+(8)^2+2(3x)(8)+[(x)^2+(2)^2 - 2(x)(2)=10x^2+92

9x^2+64+48x+(x^2+4 - 4x)=10x^2+92

9x^2+64+48x+x^2+4 -4x=10x^2+92

10x^2+44x+68=10x^2+92

44x+68=10x^2+92-10x^2

44x+68=92

44x=92-68

44x=24

x=24/44

x=6/11