Question

[(2x+3)+(x+5)]^2+[(2x+3)+(x+5)]^2=10x^2+92

Answer 1

Answer:

[(2x+3)+(x+5)]² + [(2x+3)-(x+5)=10x² +92

(2x+3+x+5)²+(2x+3-x-5)²=10x²+92

(3x+8)²+(x-2)²=10x²-92

By Identity 1

(9x²+64+48x)+(x²+4-4x) = 10x²+

92

9x²+64+48x+x²+4-4x=10x²+92

9x²+x²+48x-4x+64+4=10x²+92

10x²-44x+68=10x²+92

10x²-10x²-44x+68-92=0

0x²+44x-24=0

44x-24=0

44x=0+24

44x=24

x=24/44

x=6/11

HOPE IT HELPS

Answer 2

Step-by-step explanation:

[(2x+3)+(x+5)]^2+[(2x+3)+(x+5)]^2=10x^2+92

put the formula of (a+b)^2

[(2x+3)^2+(x+5)^2+2(2x+3)(x+5)]+[(2x+3)^2+(x+5)^2+2(2x+3)(x+5)]=10x^2+92

solve L.H.S

next step see in image