Question

[(2x+3)+(x+5)]²+[(2x+3)-(x+5)]²=10x²+92​

Answer 1

Answer:

Step-by-step explanation:

[(2x+3)+(x+5)]²+[(2x+3)-(x+5)]²=10x²+92

(3x+8)^2+(x-2)^2=10x^2+92

10x^2+68+44x=10x^2+92

44x=24

x=6/11

Answer 2

Answer

[(2x+3) + (x+5)]2 + [(2x+3) – (x+5)]2 = 10x2 + 92 Let us simplify the given equation [3x + 8]2 + [x – 2]2 = 10x2 + 92 By using the formula (a+b)2 9x2 + 48x + 64 + x2 – 4x + 4 = 10x2 + 92 By rearranging 9x2 – 10x2 + x2 + 48x – 4x = 92 – 64 – 4 44x = 24 x = 24/44 = 6/11 Let us verify the given equation now, [(2x+3) + (x+5)]2 + [(2x+3) – (x+5)]2 = 10x2 + 92 By substituting the value of ‘x’ we get, [2(6/11) + 3 + (6/11) + 5]2 + [2(6/11) + 3 – (6/11) – 5]2 = 10(6/11)2 + 92 [(12/11 + 3) + (6/11 + 5)]2 + [(12/11 + 3) – (6/11 + 5)]2 = 10(6/11)2 + 92 [(12+33)/11 + (6+55)/11]2 + [(12+33)/11- (6+55)/11]2 = 10(6/11)2 + 92 [(45/11)+ (61/11)]2 + [(45/11) – (61/11)]2 = 360/121 + 92 (106/11)2 + (-16/11)2 = (360 + 11132)/121 11236/121 + 256/121 = 11492/121 11492/121 = 11492/121

step by step explanation

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